-v^2+6v-7=2

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Solution for -v^2+6v-7=2 equation: 



-v^2+6v-7=2

We move all terms to the left:

-v^2+6v-7-(2)=0

We add all the numbers together, and all the variables

-1v^2+6v-9=0

a = -1; b = 6; c = -9;
Δ = b2-4ac
Δ = 62-4·(-1)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{-6}{-2}=+3$

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